frac3 cdot 72223 cdot 1158229992 ^ 12 cdot 5 ^ 14 = 1frac9525337033125000000000000 approx 1.003810135 https://math.stackexchange.com/questions/2487473/find-catenary-and-parabola-with-same-length-through-two-given-points
I have found a different result The parabola's equation is p(x)=k x^2-4 k+cosh 2 p'(x)=2kx L=int_-2^2 sqrt1+4 k^2 x^2 , dx=2 sqrt16 k^2+1+frac extarcsinh(4 k)2 k và from ...

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Yes, substitute x=a cosht, dx=a sinht dt, get aint dt sinht anh(t/2) = aint dt: 2 sinh^2(t/2) or the integral equals a int dt : (cosht-1) = a (sinht-t)+C = a left < sqrtfracx^2a^2-1 - mathrmarccoshleft(fracxa ight) ight >+C ...
https://physics.stackexchange.com/questions/240342/clock-on-constantly-accelerating-object-approaches-gudermannian-limit
You vị not need general relativity khổng lồ solve for motion in a flat spacetime. Using general relativity for a flat spacetime problem would be lượt thích using Riemannian geometry (the geometry of curved ...
When x>1, an alternative definition of Q_n(x) is used where the lnfrac1+x1-x is replaced with lnfracx+1x-1 so that the functions are real. Actually Q_n(x) tends khổng lồ zero as x ightarrowinfty ...
https://math.stackexchange.com/questions/177595/an-interesting-pattern-in-solutions-to-differential-equations
Great observation! Yes, this is a very meaningful connection. Let me introduce a bit of notation which I hope will be suggestive. Instead of f'(t), write D f. The symbol D here is a ...

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If s is arclength và T(s) is the unit tangent, then the curvature is T'(s)cdot n(s). Since you did not parametrize with respect lớn s, you have to lớn take into tài khoản that (excusing notational ...
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